Lời giải:
Ta có:
\(A=\left(5+\frac{1}{5}-\frac{2}{9}\right)-\left(2-\frac{1}{23}-2\frac{3}{35}+\frac{5}{6}\right)-\left(8+\frac{2}{7}-\frac{1}{18}\right)\)
\(A=5+\frac{1}{5}-\frac{2}{9}-2+\frac{1}{23}+2+\frac{3}{35}-\frac{5}{6}-8-\frac{2}{7}+\frac{1}{18}\)
\(A=\left(5-2+2-8\right)+\left(\frac{1}{5}+\frac{3}{35}-\frac{2}{7}\right)-\left(\frac{2}{9}+\frac{5}{6}-\frac{1}{18}\right)+\frac{1}{23}\)
\(A=-3+\left(\frac{7+3-10}{35}\right)-\left(\frac{4+15-1}{18}\right)+\frac{1}{23}\)
\(A=-3+0-1+\frac{1}{23}\)
\(A=-\frac{91}{23}\) . Vậy: \(A=-\frac{91}{23}\)
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