\(-\left(\dfrac{4}{1.5}+\dfrac{4}{5.9}+\dfrac{4}{9.13}...+\dfrac{4}{n\left(n+4\right)}\right)\) \(=-\left(1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{13}+...+\dfrac{1}{n}+\dfrac{1}{n+4}\right)=-\left(1-\dfrac{1}{n+4}\right)=-1+\dfrac{1}{n+4}\)
a,Tính M= \(-\dfrac{4}{1.5}-\dfrac{4}{5.9}-..........-\dfrac{4}{\left(n+4\right).n}\)
b, Tìm x biết:
-4x ( x-5)-2x(8-2x)=-3
Tìm x:
\(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x-9=5\right|\)
\(\left|x-2\right|+\left|x-3\right|+\left|2x-8\right|=9\\ \left|x+2\right|+\left|x+3\right|+\left|x+1\right|=4\\ \left|x+\dfrac{1}{1.5}\right|+\left|x+\dfrac{1}{5.9}\right|+\left|x+\dfrac{1}{9.13}\right|+...+\left|x+\dfrac{1}{397.401}\right|=101x\)
\(VT=\dfrac{1}{1.5}+\dfrac{1}{5.9}+...+\dfrac{1}{\left(4n-3\right)\left(4n+1\right)}\)
\(VT=\dfrac{1}{4}\left(1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+...+\dfrac{1}{4n-3}-\dfrac{1}{4n+1}\right)\)
\(VT=\dfrac{1}{4}\left(1-\dfrac{1}{4n+1}\right)\)
\(VT=\dfrac{1}{4}\left(\dfrac{4n}{4n+1}\right)\)
\(VT=\dfrac{4n}{16n+4}=\dfrac{4n}{4\left(4n+1\right)}=\dfrac{n}{4n+1}=VP\)
Xảy ra với mọi \(n\in Z^+\)
@Đặng Thị Cẩm Tú
1) \(25^{10}.\left(\dfrac{1}{5}\right)^{20}+\left(\dfrac{-3}{4}\right)^8.\left(\dfrac{-4}{3}\right)^8-2018^0\)
2) \(\left(\dfrac{5}{2}-\dfrac{4}{3}\right).\dfrac{6}{7}+\left(\dfrac{-3}{2}\right)^5:\left(\dfrac{-3}{2}\right)^3\)
3) \(\dfrac{4^5.9^4-2.6^9}{3^8.2^{10}+6^8.20}\)
A= \(1-\dfrac{3}{4}+\left(\dfrac{3}{4}\right)^2-\left(\dfrac{3}{4}\right)^3+\left(\dfrac{3}{4}\right)^4-...-\left(\dfrac{3}{4}\right)^{2009}+\left(\dfrac{3}{4}\right)^{2010}\)
Chứng tỏ A ko phải là số nguyên
Chứng minh:
\(A=\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}+...+\dfrac{1}{18.19.20}< \dfrac{1}{4}\)
\(B=\dfrac{36}{1.3.5}+\dfrac{36}{5.7.9}+\dfrac{36}{9.11.13}+...+\dfrac{36}{25.27.29}< 3\)
\(C=\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{n^2}\in< 1\left(n\in N,n\ge2\right)\)
\(D=\dfrac{1}{4^2}+\dfrac{1}{6^2}+\dfrac{1}{8^2}+...+\dfrac{1}{\left(2n\right)^2}< 4\left(n\in N,n\ge2\right)\)
\(E=\dfrac{2!}{3!}+\dfrac{2!}{4!}+\dfrac{2!}{5!}+...+\dfrac{2!}{n!}< 1\left(n\in N,n\ge3\right)\)
1 (5 điểm)
a) Tính giá trị biểu thức: \(L=\left(-\dfrac{3}{4}+\dfrac{4}{11}\right):\dfrac{7}{11}+\left(-\dfrac{4}{7}+\dfrac{7}{11}\right):\dfrac{7}{11}\)
b) Tính giá trị nhỏ nhất của biểu thức: \(L=\left[\left(x+1\right)^2+3\right]^2+\left|y-5\right|+2008\)
2(4 điểm)
a) Tìm 3 số x;y;z thỏa mãn \(20x=15y=12z\) và \(2x^2+2y^2-3z^2=-100\)
b) Cho đa thức \(L_1\left(x\right)=x^2+2xm+m^2\) và \(L_2\left(x\right)=x^2+\left(2x+1\right)x+m^2\)
Tìm m biết \(L_1\left(1\right)=L_2\left(-1\right)\)
3(4 điểm)
a) Chứng minh \(5^{n+3}-3^{n+3}+5^{n+2}-3^{n+1}⋮60\) với mọi n thuộc N
b) Chứng minh \(\dfrac{1}{4}+\dfrac{2}{4^2}+\dfrac{3}{4^3}+\dfrac{4}{4^4}+...+\dfrac{2017}{4^{2017}}< \dfrac{1}{2}\)
6 điểm được free ạ =)))))
Cho biểu thức:
\(A=1-\dfrac{3}{4}+\left(\dfrac{3}{4}\right)^2-\left(\dfrac{3}{4}\right)^3+\left(\dfrac{3}{4}\right)^4-...+\left(\dfrac{3}{4}\right)^{2016}-\left(\dfrac{3}{4}\right)^{2017}\)
Chứng tỏ rằng a không phải là một số nguyên.
Tìm số nguyên x biết: a) \(-4\dfrac{3}{5}.2\dfrac{4}{23}\le x\le-2\dfrac{3}{5}:1\dfrac{6}{15}\)
b)\(-4\dfrac{1}{3}.\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\le x\le-\dfrac{2}{3}\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
