Question

Tính

\(\left(0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}\right):\left(\dfrac{11}{7}+\dfrac{11}{3}+2,75-2,2\right)\)

Answer 1

=\(\left(\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{13}\right):\left(\dfrac{11}{7}+\dfrac{11}{13}+\dfrac{11}{4}-\dfrac{11}{5}\right)\)

=\(\left(3.\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)\right):\left(11\left(\dfrac{1}{7}+\dfrac{1}{13}+\dfrac{1}{4}-\dfrac{1}{5}\right)\right)\)

= \(\dfrac{3}{11}\)

Mình sửa số chia thành \(\left(\dfrac{11}{7}+\dfrac{11}{13}+2,75-2,2\right)\)