CHÚC BẠN HỌC TỐT!!
(Câu cuối hơi kì thì phải??!!)
+) Ta có: \(\left\{{}\begin{matrix}m_{Cu}=0,23.80=18,4\left(g\right)\\\%Cu=\dfrac{64}{64+16}.100\%=80\%\end{matrix}\right.\)
\(\Rightarrow m_{Cu}=18,4.80\%=14,72\left(g\right)\)
+) Ta có: \(\left\{{}\begin{matrix}m_{CuSO4}=12\left(g\right)\\\%Cu=\dfrac{64}{64+32+4.16}.100\%=40\%\end{matrix}\right.\)
\(\Rightarrow m_{Cu}=12.40\%=4,8\left(g\right)\)
+) Ta có: \(n_{CuSO4}=\dfrac{5}{64+32+4.16+5.\left(2.1+16\right)}=0,02\left(mol\right)\)
\(\Rightarrow m_{CuSO4}=160.0,02=3,2\left(g\right)\)
\(\left\{{}\begin{matrix}m_{CuSO4}=3,2\left(g\right)\\\%Cu=\dfrac{64}{64+32+4.16}.100\%=40\%\end{matrix}\right.\)
\(\Rightarrow m_{Cu}=3,2.40\%=1,28\left(g\right)\)
+) Câu cuối chất không có Cu mà bạn!!?
