\(d_A\)/ \(H_2\)= \(\dfrac{M_A}{M_{H_2}}=16\)
=> \(M_A=16.M_{H_2}=16.2=32\)(g/mol)
d\(\frac{A}{H_2}=16\) => \(M_A\)= 16.2=32 (g) => \(O_2\)
d\(\frac{B}{H_2}=8\) => \(M_B\)= 8.2=16 (g) => \(NH_2\)
d\(\frac{C}{H_2}=\)14 => \(M_C\) = 14.2= 28 (g) => \(N_2\)
d\(\frac{D}{H_2}\) = 35,5 => \(M_D\) = 35,5.2= 71 (g) => \(Cl_2\)
d\(\frac{E}{H_2}\) = 22 =>\(M_E\) = 22.2= 44 => \(CO_2\)