Question

Tính khối lượng của:

a. 0,5 mol S b. 1,5 mol N₂ c. 0,25 mol Al₂O₃ d. 3.10²³ nguyên tử H

e. 33,6 lít O₂ f. 9.10²³ phân tử SO₃

Answer 1

a) \(m_S=n_S.M_S=0,5.32=16\left(g\right)\)

b) \(m_{N_2}=n_{N_2}.M_{N_2}=1,5.28=42\left(g\right)\)

c) \(m_{Al_2O_3}=n_{Al_2O_3}.M_{Al_2O_3}=0,25.102=25,5\left(g\right)\)

d) \(n_H=\dfrac{3.10^{23}}{6.10^{23}}=0,5\left(mol\right)\\ \Rightarrow m_H=n_H.M_H=0,5.1=0,5\left(g\right)\)

e) \(n_{O_2}=\dfrac{V_{O_2\left(đktc\right)}}{22,4}=\dfrac{33,6}{22,4}=1,5\left(mol\right)\\ \Rightarrow m_{O_2}=n_{O_2}.M_{O_2}=1,5.32=48\left(g\right)\)

f) \(n_{SO_3}=\dfrac{9.10^{23}}{6.10^{23}}=1,5\left(mol\right)\\ \Rightarrow m_{SO_3}=n_{SO_3}.M_{SO_3}=1,5.80=120\left(g\right)\)