Question

Tính giá trị biểu thức

\(N=\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(M=\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)

\(T=\dfrac{45^{10}.5^{20}}{75^{15}}\)

Answer 1

M=\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{4^{20}\left(2^{20}+1\right)}{4^{25}+4^{15}}=\dfrac{4^{20}\left(2^{20}+1\right)}{4^{15}\left(4^{10}+1\right)}=\dfrac{2^{20}+1}{4^{10}+1}\)

Answer 2

T=\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{9^{10}.5^{30}}{25^{15}.3^{15}}=\dfrac{3^{20}.5^{30}}{5^{30}.3^{15}}=3^5=243\)