\(\dfrac{27.18+27.103-120.27}{15.13+33.12}\)
\(=\dfrac{27\left(18+103-120\right)}{15.13+33.12}\)
\(=\dfrac{27}{15.13+33.12}\)
\(=\dfrac{27}{195+396}\)
\(=\dfrac{27}{591}\)
\(=\dfrac{9}{197}\)
\(\dfrac{27.18+27.103-120.27}{15.13+33.12}\)
\(=\dfrac{27\left(18+103-120\right)}{15.13+33.12}\)
\(=\dfrac{27}{15.13+33.12}\)
\(=\dfrac{27}{195+396}\)
\(=\dfrac{27}{591}\)
\(=\dfrac{9}{197}\)
Tìm số nguyên x, biết :
a) 10 - x = 18 - ( 27 - 9 )
b) x - 24 = -12 - 15
c) 25 - ( x - 6 ) = -1
d) -49 - x - 13 = -6
Bai 1 : Tinh a) 24 - (-15) - 2 b) (-85) + 10 - (-85) - 50 c) 71 - (-30) - (+18) + (-30)
d) -(30) - (+37) + (+37) + (-85) e) (35-815) - (795-65) g) (2002-79+15) + (-79+15)
h) -(515-80+91) - (2003+80-91)
Bai 2: Tim x,biet a) 25 - (30+x) = x - (27-8) b) (x-12) - 15 = (20-17) - (18+x) c) 15 - x = 7 - (-2) d) x - 35 = (-12) - 3 e) I5-xI - 26 = - 15
Tinh gia tri bieu thuc
a, A = x^2 + x - 5 voi x = -3
b, B = | x -1 | + | x +9| voi x = -81
c, C = -7x^3 × | x -1| + 42 voi x = -1
d, D= -(x -1) × (x+2) voi |x| = 2
1.Tinh gia tri cua bieu thuc
\(\dfrac{1}{2}+\dfrac{1}{3}\).x-\(\dfrac{1}{6}\).x voi x=\(\dfrac{-3}{5}\)
Bai 14 :Tim cac gia tri cua x de bieu thuc sau nhan gia tri duong:
a) 3x-2 b)x2-5x
Bai13: Tim cac gia tri xde bieu thuc sau nhan gia tri am:
a)9-3x b) (2x-4).(x+5) c)\(\dfrac{x+4}{x-2}\)
tính giá trị biểu thức:
D=13 x 4^6 x ( 28 và 7 phần 13 - 27 và 5 phần 18) / 59 x 2^12 x ( 5 phần 14 + 5 phần 84 + 5 phần 204 + 5 phần 374 ).
A=\(\frac{\left(1^3+2^3+3^3+...+10^3\right)\cdot\left(x^2+y^2\right)\cdot\left(x^3+y^3\right)\cdot\left(x^4+y^4\right)}{1^2+2^2+3^2+...+10^2}\)
Tinh gia tri bieu thuc
\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)