Question

tính

\(\dfrac{6^6+6^3.3^3+3^6}{-73}\)

Answer 1

\(\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(=\dfrac{\left(2.3\right)^6+\left(2.3\right)^3.3^3+3^6}{-73}\)

\(=\dfrac{2^6.3^6+2^3.3^6+3^6}{-73}\)

\(=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}\)

\(=\dfrac{3^6.73}{-73}=-1.3^6=-3^6\)