Question

Tính đạo hàm y=sin(π/2+2x) là

Answer 1

X = -0.785398163

L-R = 0

Answer 2

\(y=sin\left(\frac{\pi}{2}+2x\right)=cos\left(\frac{\pi}{2}-\frac{\pi}{2}-2x\right)=cos\left(-2x\right)=cos2x\)

\(\Rightarrow y'=-2sin2x\)

Answer 3

\(y'=\left(\frac{\pi}{2}+2x\right)^'\cdot cos\left(\frac{\pi}{2}+2x\right)=2cos\left(\frac{\pi}{2}+2x\right)\)

Answer 4

y'=(\(\frac{\pi}{2}\)+2)'cos(\(\frac{\pi}{2}\)+2)=2cos(\(\frac{\pi}{2}\)+2)