* Ta có: \(\left\{{}\begin{matrix}n_{NaOH}=0,4\left(mol\right)\\n_{KOH}=0,2\left(mol\right)\end{matrix}\right.\)\(\Rightarrow n_{OH^-}=0,6\left(mol\right)\)
\(H^+\left(0,6\right)+OH^-\left(0,6\right)\rightarrow H_2O\)
Ta có: \(n_{H^+}=2.n_{H_2SO_4}=0,6\left(mol\right)\)
\(\Rightarrow n_{H_2SO_4}=0,3\left(mol\right)\)
\(\Rightarrow C_{M_{H_2SO_4}}=\dfrac{0,3}{0,3}=1\left(M\right)\)
* Ta có: \(\left\{{}\begin{matrix}n_{H_2SO_4}=0,4\left(mol\right)\\n_{HCl}=0,05\left(mol\right)\end{matrix}\right.\)\(\Rightarrow n_{H^+}=2n_{H_2SO_4}+n_{HCl}=0,4.2+0,05=0,85\left(mol\right)\)
\(OH^-\left(0,85\right)+H^+\left(0,85\right)\rightarrow H_2O\)
Ta có: \(n_{OH^-}=n_{NaOH}=0,85\left(mol\right)\)
\(\Rightarrow C_{M_{NaOH}}=\dfrac{0,85}{0,3}=\dfrac{17}{6}\left(M\right)\)
