Ta có: \(\widehat{C}-\widehat{B}=36^0\Rightarrow\widehat{C}=\widehat{B}+36^0\)
Xét tam giác ABC có:
\(\widehat{A}+\widehat{B}+\widehat{C}=180^0\)
\(\Rightarrow2\widehat{B}+\widehat{B}+\widehat{B}+36^0=180^0\Rightarrow\widehat{B}=36^0\)
\(\Rightarrow\left\{{}\begin{matrix}\widehat{A}=2\widehat{B}=72^0\\\widehat{C}=\widehat{B}+36^0=72^0\end{matrix}\right.\)