\(\left|17x-5\right|-\left|17x+5\right|=0\)
+) Xét \(x\ge\dfrac{5}{17}\) có:
\(17x-5-17x-5=0\Rightarrow-10=0\) ( vô lí )
+) Xét \(\dfrac{-5}{17}\le x< \dfrac{5}{17}\) có:
\(5-17x-17x-5=0\Rightarrow-34x=0\Rightarrow x=0\) ( t/m )
+) Xét \(x< \dfrac{-5}{17}\) có:
\(5-17x+17x+5=0\)
\(\Rightarrow10=0\) ( vô lí )
Vậy x = 0