Question

Tính

B= \(\dfrac{2016.2018-1}{2018+2016.2017}\)

Answer 1

\(=\dfrac{2017^2-1-1}{2017+1+2017\left(2017-1\right)}\)

\(=\dfrac{2017^2-2}{2017^2+2017+1-2017}=\dfrac{2017^2-2}{2017^2+1}\)