Ta có: \(A=\left(0,25\right)^{-1}.\dfrac{1}{4}^{-2}.\dfrac{4}{3}^{-2}.\dfrac{5}{4}^{-1}.\dfrac{2}{3}^{-3}\)
--> A= \(\left(\dfrac{\dfrac{1}{1}}{4}\right).\left(\dfrac{\dfrac{1}{1}}{4^2}\right).\left(\dfrac{\dfrac{1}{4^2}}{3^2}\right).\left(\dfrac{\dfrac{1}{5}}{4}\right).\left(\dfrac{\dfrac{1}{2^3}}{3^3}\right)\)
--> A= 4.42. \(\dfrac{3^2}{4^2}\).\(\dfrac{4}{5}\) . \(\dfrac{3^3}{2^3}\)
--> A= \(\dfrac{4.4^2.3^2.3^3}{4^{2.}.5.2^3}=\dfrac{2.3^5}{5}=\dfrac{2.243}{5}\)
--> A= 97,2
\(A=\left(0,25\right)^{-1}.\left(\dfrac{1}{4}\right)^{-2}.\left(\dfrac{4}{3}\right)^{-2}.\left(\dfrac{5}{4}\right)^{-1}.\left(\dfrac{2}{3}\right)^{-3}\)
\(A=\left[\left(\dfrac{1}{4}\right)^{-1}.\left(\dfrac{5}{4}\right)^{-1}\right]\left[\left(\dfrac{1}{4}\right)^{-2}.\left(\dfrac{4}{3}\right)^{-2}\right].\left(\dfrac{2}{3}\right)^{-3}\)
\(A=\left(\dfrac{5}{16}\right)^{-1}.\left(\dfrac{1}{3}\right)^{-2}.\left(\dfrac{2}{3}\right)^{-3}\)
\(A=\dfrac{16}{5}.9.\dfrac{27}{8}\)
\(A=\dfrac{2.9.27}{5}=\dfrac{486}{5}=97,2\)
#chucbanhoctotnhe 
