Question

tính

a)\([\begin{matrix}-2\\3\end{matrix}+0,5\div\left(\dfrac{-3}{2}\right)^2]+[1\dfrac{1}{5}-1,4\times\dfrac{5}{6}+6\)

b)(-0,2)²\(\times\)5 \(-\)\(\dfrac{8^2\times9^5}{3^9\times4^3}\)

Answer 1

a)

\(\left[\dfrac{-2}{3}+0,5:\left(\dfrac{-3}{2}\right)^2\right]+\left[1\dfrac{1}{5}-1,4.\dfrac{5}{6}+6\right]\\ =\left[\dfrac{-2}{3}+\dfrac{1}{2}:\dfrac{9}{4}\right]+\left[\dfrac{6}{5}-\dfrac{7}{5}.\dfrac{5}{6}+6\right]\\ =\left[\dfrac{-2}{3}+\dfrac{1}{2}.\dfrac{4}{9}\right]+\left[\dfrac{6}{5}-\dfrac{7}{6}+6\right]\\ =\left[\dfrac{-2}{3}+\dfrac{2}{3}\right]+\left[\dfrac{36}{30}-\dfrac{35}{30}+6\right]\\ =0+\left[\dfrac{1}{30}+6\right]\\ =6\dfrac{1}{30}\)

b)

\(\left(-0,2\right)^2.5-\dfrac{8^2.9^5}{3^9.4^3}\\ =0,4.5-\dfrac{\left(2^3\right)^2.\left(3^2\right)^5}{3^9.\left(2^2\right)^3}\\ =2-\dfrac{2^6.3^{10}}{3^9.2^6}\\ =2-\dfrac{1.3}{1.1}\\ =2-3\\ =-1\)

Answer 2

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