Question

Tính

a)(2x+1).(2x-1)-4x^2

b)(2x^2+y).(2x^2-y)-4x^2+y^2

c)(2x^2+y)^2-(2x^2-y)^2

d)(2x^3y+y)^2_(y-2x^3y)^2

Answer 1

a/ \(\left(2x+1\right)\left(2x-1\right)-4x^2=\left(2x\right)^2-1^2-4x^2\)

\(=4x^2-1-4x^2\)

b/ \(\left(2x^2+y\right)\left(2x^2-y\right)-4x^2+y^2\)

\(=\left(2x^2\right)^2-y^2-4x^2+y^2=4x^4-y^2-4x^2+y^2=4x^4-4x^2\)

c/ \(\left(2x^2+y\right)^2-\left(2x^2-y\right)^2\)

\(=\left(2x^2+y+2x^2-y\right)\left(2x^2+y-2x^2+y\right)\)

\(=4x^2\cdot2y=8x^2y\)

d/ \(\left(2x^3y+y\right)^2-\left(y-2x^3y\right)^2=\left(2x^3y+y\right)^2-\left(2x^3y-y\right)^2\)

\(=\left(2x^3y+y+2x^3y-y\right)\left(2x^3y+y-2x^3y+y\right)\)

\(=4x^3y\cdot2y=8x^3y^2\)