Question

tính

a/(-x²y5)²: (-x²y⁵)

b/ 5(x-2y)³: (5x-10y)

tại x =\(\frac{1}{2}\), y =1

giúp mình với ạ

Answer 1

https://i.imgur.com/9wb6VDD.jpg

Answer 2

a)\(\left(-x^2y^5\right)^2:\left(-x^2y^5\right)=\left(-x^2y^5\right)\)

b)\(5\cdot\left(x-2y\right)^3:\left(5x-10y\right)\)

\(=5\cdot\left(x-2y\right)\cdot\left(x-2y\right)^2:\left(5x-10y\right)\)

\(=\left(5x-10y\right)\cdot\left(x-2y\right)^2:\left(5x-10y\right)\)

\(=\left(x-2y\right)^2\)

Thay \(x=\frac{1}{2},y=1\) vào:

\(\left(\frac{1}{2}-2\cdot1\right)^2=\left(\frac{-3}{2}\right)^2=\frac{9}{4}\)