\(\dfrac{-1}{42}+\dfrac{3}{48}=\dfrac{-1}{42}+\dfrac{1}{16}=\dfrac{-8}{336}+\dfrac{21}{336}=\dfrac{13}{336}\)
\(\dfrac{-1}{42}+\dfrac{3}{48}=\dfrac{-8}{336}+\dfrac{21}{336}=\dfrac{\left(-8\right)+21}{336}=\dfrac{13}{336}\)
\(\dfrac{-1}{42}+\dfrac{3}{48}=\dfrac{-1}{42}+\dfrac{1}{16}=\dfrac{-8}{336}+\dfrac{21}{336}=\dfrac{13}{336}\)
\(\dfrac{-1}{42}+\dfrac{3}{48}=\dfrac{-8}{336}+\dfrac{21}{336}=\dfrac{\left(-8\right)+21}{336}=\dfrac{13}{336}\)
Tính nhanh
A=1+\(\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{48}+\dfrac{1}{80}+\dfrac{1}{120}\)
1 phần 20 + 1 phần 30 + 1phaanf 42 ... + 1 phần 90 = ???
tính nhanh: 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56
Tính tổng
A=1/8+1/24+1/48+1/80+...+1/360
Tính các tổng dưới đây sau khi đã rút gọn phân số :
a) \(\dfrac{7}{21}+\dfrac{9}{-36}\)
b) \(\dfrac{-12}{18}+\dfrac{-21}{35}\)
c) \(\dfrac{-3}{21}+\dfrac{6}{42}\)
d) \(\dfrac{-18}{24}+\dfrac{15}{-21}\)
tính giá trị của biểu thức sau A=1/30+1/42+1/56+1/72+1/90+1/110+1/132
HELP ME!!!
TÍNH NHANH:
A=\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{9900}\)
B=\(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+...+\dfrac{1}{95}\)
C=\(\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{48}+...+\dfrac{1}{9800}\)
*D=\(\dfrac{2}{3.5}+\dfrac{3}{5.8}+\dfrac{11}{8.19}+\dfrac{13}{19.32}+\dfrac{25}{32.57}+\dfrac{30}{57.87}\)
Tổng của 3 phân số \(\dfrac{1}{3},\dfrac{4}{7},\dfrac{-5}{21}\) bằng :
(A) \(\dfrac{2}{3}\) (B) \(\dfrac{3}{31}\) (C) \(\dfrac{24}{21}\) (D) \(\dfrac{27}{42}\)
Hãy chọn đáp số đúng ?
\(\frac{x-2}{12}+\frac{x-2}{20}+\frac{x-2}{30}+\frac{x-2}{42}=42^5:\left(2^3.21^6\right)\)
Giúp mk nha!!!!!!