Ta có : 12,(1) = 12 + 0,(1) = 12 + \(\dfrac{1}{9}\)=\(\dfrac{109}{9}\)
2,3(6) = 2,3 + \(\dfrac{1}{10}.0,\left(6\right)=2,3+\dfrac{1}{10}.6.0,\left(1\right)=2,3+\dfrac{1}{10}.6.\dfrac{1}{9}=\dfrac{71}{30}\)
4,(21)=4+21.0,(01)=4+21.\(\dfrac{1}{99}=\dfrac{139}{33}\)
\(\Rightarrow\left[\dfrac{109}{9}-\dfrac{71}{30}\right]:\dfrac{139}{33}=\dfrac{9647}{4170}\)