Lời giải:
\(0,\left(6\right)+0,8\left(3\right)-0,75\)
\(=\dfrac{2}{3}+\dfrac{5}{6}-\dfrac{3}{4}\)
\(=\dfrac{8}{12}+\dfrac{10}{12}-\dfrac{9}{12}\)
\(=\dfrac{8+10-9}{12}\)
\(=\dfrac{9}{12}=\dfrac{3}{4}=0,75\)
Vậy giá trị của biểu thức trên là 0,75
0,5+0,(3)-0,1(6)/2,5+1(6)-0,8(3)
0,5+0,(3)-0,1(6)/2,5+1,(6)-0,8(3)
tính \(\dfrac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
tính nhanh nếu có the: \(\dfrac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
jup mk mk cần gâp, mk tick cho
Tính:
\(\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
:::::dấu ngoặc ở trên là chu kì nha mn:::::::::::::::::::::::
bt.1 tính
a )-1/12 - (2 trên 5/8 - 1/3)
b 18/ 39 . (- 1 trên 5/8 ) : (-6 trên 3/4 )
c ) 0,75 -0,6 + 3/7 + 3/15 phần 2 ,75 - 2,2 + 11/7 +11/17
\(\dfrac{\left(0,8^5\right)}{\left(0,4^6\right)}\)
\(a.A=[\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}]+\frac{1890}{2005}+115\)
b.B=\(\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\cdot\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(42-5\frac{1}{3}\right)}\cdot\left(-1\frac{19}{93}\right)\right]\cdot\frac{31}{50}\)
Câu 1: Tính
1) \(\dfrac{0,375-0,3+\dfrac{3}{11}+\dfrac{3}{12}}{-0,625+0,5-\dfrac{5}{11}-\dfrac{5}{12}}+\dfrac{1,5+1-0,75}{2,5+\dfrac{5}{3}-1,25}\)
2) \(\dfrac{\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}}{\dfrac{2}{3}-\dfrac{2}{7}-\dfrac{2}{13}}.\dfrac{\dfrac{1}{2}-0,25+0,2}{\dfrac{7}{6}-0,875+0,7}+\dfrac{6}{7}\)
