Question

 Tìm x∈Z ,biết

3 ( x -2 ) + 4(x-5)= 23

Answer 1

\(3\left(x-2\right)+4\left(x-5\right)=23\)

\(\Rightarrow3x-6+4x-20-23=0\)

\(\Rightarrow7x-49=0\)

\(\Rightarrow x=7\)

Answer 2

    3(x-2)+4(x-5)=23

<=>3x-6+4x-20=23

<=>7x-26=23

<=>7x=49

<=>x=7

Vậy x=7

Answer 3

3 ( x -2 ) + 4(x-5)= 23

=> 3x-6+4x-20   =23

=> 7x-26            =23

=>  7x                 =23+26=49

=>         x            =\(\dfrac{49}{7}\)=7

Vậy x=7.

Answer 4

Ta có: \(3\left(x-2\right)+4\left(x-5\right)=23\)

\(\Leftrightarrow3x-6+4x-20-23=0\)

\(\Leftrightarrow7x-49=0\)

\(\Leftrightarrow7x=49\)

hay x=7(thỏa mãn)

Vậy: x=7