Question

tìm x,y thuộc z:

(x+1)(y+10)=6

Answer 1

\(\left(x+1\right)\left(y+10\right)=6\)

\(\Leftrightarrow\left(x+1\right)\left(y+10\right)=1\cdot6\)

\(\Leftrightarrow\left[{}\begin{matrix}\left(x+1\right)\left(y+10\right)=1\\\left(x+1\right)\left(y+10\right)=6\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x+1=1\\y+10=1\\x+1=6\\y+10=6\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0;y=-9\\x=5;y=-4\end{matrix}\right.\)

Vậy có 2 cặp số x, y thỏa mãn là (0;-9) và (5;-4)