Question

Tìm x,y nguyên biết:

|x-2|+(y-3)²=0

Answer 1

Ta có:

|x-2|	0
(y-3)2	0

Với |x-2|

x-2=0

x=0+2

x=2

Với (y-3)²

(y-3)²=0

Vì (y-3)²=0²

\(\Rightarrow y-3=0\)

y=0+3

y=3

Vậy(x;y)\(\in\){(2;3)}

Answer 2

Ta có: \(\left|x-2\right|\ge\) 0

\(\left(y-3\right)^2\ge0\)

\(\Rightarrow\left|x-2\right|+\left(y-3\right)^2\ge0\)

Dấu "=" xảy ra khi \(\left|x-2\right|=0\) ; \(\left(y-3\right)^2=0\)

\(\Rightarrow\left[\begin{matrix}x=2\\y=3\end{matrix}\right.\)

Vậy \(x=2;y=3.\)