Question

Tim x,y

\(\frac{x-3}{y-2}=\frac{3}{2};x-y=4\)

Answer 1

ĐKXĐ : \(y\ne2\)

\(x-y=4\Leftrightarrow x=y+4\)

Thay vào biểu thức ta được :

\(\dfrac{y+4-3}{y-2}=\dfrac{3}{2}\)

\(\Leftrightarrow\dfrac{y+1}{y-2}=\dfrac{3}{2}\)

\(\Leftrightarrow2\left(y+1\right)=3\left(y-2\right)\)

\(\Leftrightarrow2y+2=3y-6\)

\(\Leftrightarrow3y-6-2y-2=0\)

\(\Leftrightarrow y-8=0\)

\(\Leftrightarrow y=8\)( thỏa mãn )

\(\Leftrightarrow x=8+4=12\)