Question

tìm x:

\(\dfrac{x+1}{3}\)= \(\dfrac{-3}{-9}\)

Answer 1

\(\Leftrightarrow-9x-9=-9\)

\(\Leftrightarrow-9x=0\)

\(\Leftrightarrow x=0\)

Answer 2

\(\dfrac{x+1}{3}=\dfrac{3}{9}=>\left(x+1\right).9=3.3\)

\(\left(x+1\right).9=9=>x+1=1\)

=> x=0

Answer 3

\(=>-9\left(x+1\right)=9.\left(-3\right)\)

\(=>-9x-9=-9\)

\(=>-9x=0\)

\(=>x=0\)