Lời giải:
\(5x^2-5=4(x^2-2x+1)\)
\(\Leftrightarrow 5(x^2-1)=4(x-1)^2\)
\(\Leftrightarrow 5(x-1)(x+1)-4(x-1)^2=0\)
\(\Leftrightarrow (x-1)[5(x+1)-4(x-1)]=0\)
\(\Leftrightarrow (x-1)(x+9)=0\Rightarrow \left[\begin{matrix} x=1\\ x=-9\end{matrix}\right.\)