Question

Tìm x:

a) 2(x+3)-3(x-1)=10

b) x(x-1)+2(x-1)=0

Answer 1

a) 2(x+3)-3(x-1)=10

\(VT=-\left(x-9\right)\)

\(\Leftrightarrow-\left(x-9\right)=10\)

\(\Leftrightarrow9-x=10\)

\(\Leftrightarrow x=-1\)

b)x(x-1)+2(x-1)=0

\(\Leftrightarrow\left(x+2\right)\left(x-1\right)=0\)

\(\Leftrightarrow x+2=0\) hoặc \(x-1=0\)

\(\Leftrightarrow x=-2\) hoặc\(x=1\)

 

Answer 2

a) 2(x+3)-3(x-1)=10

=>2x+6-3x+3=10

=>9-x=10

=>x=9-10

=>x=-1

b) x(x-1)+2(x-1)=0

=>(x+2)(x-1)=0

=>x+2=0 hoặc x-1=0

+)Nếu x+2=0

=>x=0-2=-2

+)Nếu x-1=0

=>x=0+1=1

Vậy x\(\in\){-2;1}

Answer 3

a) 2(x+3)-3(x-1)=10

   2x +6 -3x +3 = 10

   2x -3x = 10 -6-3

   -x= 1

    x= -1

b) x(x-1) + 2(x-1) =0

    (x+2) (x-1) =0

Nếu x+2= 0 thì x= -2

Nếu x-1 = 0 thì x=1

Vậy x=-2 hoặc x=1