a) 2x-3=-x+6
2x - 3 + x - 6 =0
3x -9 = 0
3x = 9
x = 9 : 3
x= 3
c/ \(\left(-12x-4^3\right).8^3=4.8^4\)
\(\left(-12x-64\right).512=16384\)
\(-12x-64=\dfrac{16384}{512}=32\)
\(-12x=32+64=96\)
\(x=\dfrac{96}{\left(-12\right)}=-8\)
a, 2x-3=-x+6
\(\Leftrightarrow\)2x-3+x-6=0
\(\Leftrightarrow\)3x-9=0
\(\Leftrightarrow\)3x=9
\(\Leftrightarrow\)x=3
a) Ta có: \(2x-3=-x+6\)
\(\Leftrightarrow2x+x=6+3\)
\(\Leftrightarrow3x=9\)
hay x=3
Vậy: x=3
b) Ta có: \(\left|2x-7\right|+2=13\)
\(\Leftrightarrow\left|2x-7\right|=11\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-7=11\\2x-7=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=18\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=-2\end{matrix}\right.\)
Vậy: \(x\in\left\{9;-2\right\}\)
c) Ta có: \(\left(-12x-4^3\right)\cdot8^3=4\cdot8^4\)
\(\Leftrightarrow\left(-12x-64\right)=\dfrac{4\cdot8^4}{8^3}=32\)
\(\Leftrightarrow-12x=96\)
hay x=-8
Vậy: x=-8
a) 2x - 3 = -x + 6
\(\Leftrightarrow\) 2x - 3 + x - 6 = 0
\(\Leftrightarrow\) 3x - 9 = 0
\(\Leftrightarrow\) 3x = 9
\(\Leftrightarrow\) x = 3
b) |2x - 7| + 2 = 13
\(\Leftrightarrow\) |2x - 7| = 11
\(\Leftrightarrow\) 2x - 7 \(\in\) {\(\pm\)11}
\(\Leftrightarrow\) 2x \(\in\) {18 ; - 4}
\(\Leftrightarrow\) x \(\in\) {9 ; - 2}
c) (-12x - 43). 83 = 4.84
\(\Leftrightarrow\) (-12x - 64). 29 = 22. 212
\(\Leftrightarrow\) (-12x - 64). 29 = 214
\(\Leftrightarrow\) -12x - 64 = 25 = 32
\(\Leftrightarrow\) -12x = 96
\(\Leftrightarrow\) x = - 8
a) 2x-3=-x+6
\(\Leftrightarrow\)2x - 3 + x - 6 =0
\(\Leftrightarrow\)3x -9 = 0
\(\Leftrightarrow\)3x = 9
\(\Leftrightarrow\)x = 9 : 3
\(\Leftrightarrow\)x= 3
Vậy x=3
c/ (−12x−43).83=4.84
\(\Leftrightarrow\)(−12x−64)=4.84 : 83
\(\Leftrightarrow\)x=96(−12)=−8
a) 2x-3=-x+6
2x - 3 + x - 6 =0
3x -9 = 0
3x = 9
x = 9 : 3
x= 3
