Question

Tìm x

a) 1/2x .(4x-3) + 3x(-2/3x + 1) = 1/3

Answer 1

     \(\frac{1}{2}\).(4x-3)+3x(-\(\frac{2}{3}\)x+1)=\(\frac{1}{3}\)

<=>2x\(^2\)- \(\frac{3}{2}\)x-2x\(^2\)+3x=\(\frac{1}{3}\)

<=> (2x\(^2\)-2x\(^2\)) - (\(\frac{3}{2}\)x+3x)=\(\frac{1}{3}\)

<=>  \(\frac{3}{2}\)x=\(\frac{1}{3}\)

<=>   x= \(\frac{2}{9}\)

Vậy x= 2/9

Answer 2

↔ \(2x^2-\frac{3}{2}x-2x^2+3x=\frac{1}{3}\)

↔ \(\left(2x^2-2x^2\right)-\left(\frac{3}{2}+3x\right)=\frac{1}{3}\)

↔ \(\frac{3}{2x}=\frac{1}{3}\)

↔ \(x=\frac{1}{3}\div\frac{3}{2}\)

→ \(x=\frac{2}{9}\)

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