Question

tim x

9(4x+3)²=16(3x-5)²

Answer 1

\(9\left(4x+3\right)^2=16\left(3x-5\right)^2\)

\(\Rightarrow9\left(16x^2+24x+9\right)=144x^2-480x+400\)

\(\Rightarrow696x=319\)

\(\Rightarrow x=319:696\)

\(\Rightarrow x=\frac{11}{24}\)

 

Answer 2

\(9\left(4x+3\right)^2=16\left(3x-5\right)^2\)

=> \(3^2\left(4x+3\right)^2-4^2\left(3x-5\right)^2=0\)

=> \(\left(12x+9\right)^2-\left(12x-20\right)^2=0\)

=> \(\left(12x+9-12x-20\right)\left(12x+9+12x+20\right)=0\)

=> \(-11\left(24x+29\right)=0\)

=> x = -29/24

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