Tìm x:
Ta có: \(3\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\)
\(\Rightarrow3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\)
\(\Rightarrow3x-5x+x=\dfrac{1}{5}+\dfrac{3}{2}+3\)
\(\Rightarrow-x=\dfrac{47}{10}\)
\(\Rightarrow x=-\dfrac{47}{10}\)
Vậy \(x=-\dfrac{47}{10}=-4,7\)
Ta khai triển phá ngoặc ra thì được:
\(=>3x-\dfrac{3}{2}-\left(5x+3\right)=-x+\dfrac{1}{5}\)
\(=>3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\)
\(=>-2x-\dfrac{9}{2}=-x+\dfrac{1}{5}\)
\(=>-2x+x=\dfrac{1}{5}+\dfrac{9}{2}\)
\(=>-x=\dfrac{47}{10}=4,7=>x=-\dfrac{47}{10}=-4,7\)
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