Sửa đề: Tìm số nguyên x:
\(3\dfrac{2}{3}.\left(\dfrac{1}{5}-\dfrac{1}{2}\right)\le x\le\dfrac{3}{11}.\left(\dfrac{1}{5}+\dfrac{1}{3}+\dfrac{1}{2}\right)\)
\(\Rightarrow\dfrac{11}{3}.\dfrac{-3}{10}\le x\le\dfrac{3}{11}.\dfrac{31}{30}\)
\(\Rightarrow-\dfrac{11}{10}\le x\le\dfrac{31}{110}\)
Vì \(x\in Z\) nên \(x\in\left\{-1;0\right\}\)
Vậy..............
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