a) (x + 2) . y = -3 = -1 . 3 = -3 . 1
TH1: x + 2 = -3 => x = -5
y = 1
TH2: x + 2 = -1 => x = -3
y = 3
TH3: x + 2 = 1 => x = -1
y = -3
TH4: x + 2 = 3 => x = 1
y = -1
Vậy (x ; y) = (-5 ; 1) ; (-3 ; 3) ; (-1 ; -3) ; (1 ; -1)
b) (x + 2)(y + 3) = 3 = 1 . 3 = -1 . (-3)
TH1: x + 2 = 1 => x = -1
y + 3 = 3 => y = 0
TH2: x+ 2 = 3 => x= 1
y + 3 = 1 => y = -2
TH3: x + 2 = -3 => x = -5
y + 3 = -1 => y = -4
TH4: x + 2 = -1 => x = -3
y + 3 = -3 => y = -6
Vậy (x ; y) = (-1 ; 0) ; (1 ; -2) ; (-5 ; -4) ; (-3 ; -6)