\(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\\ \Rightarrow\frac{20}{4x}+\frac{xy}{4x}=\frac{1}{8}\\ \Rightarrow\frac{20+xy}{4x}=\frac{1}{8}\\ \Rightarrow160+8xy=4x\\ \Rightarrow160-8xy-4x=0\Rightarrow8xy-4x=160\\ \Rightarrow x\left(8y-1\right)=160\)
tới đây dễ rồi