\(\left(x-2\right)^2\left(y-3\right)=-4\)
\(\Rightarrow\left(x-2\right)^2;y-3\inƯ\left(4\right)\)
\(Ư\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
Mà :
\(\left(x-2\right)^2\ge0\)
\(\left(x-2\right)^2\)là số chính phương
\(\Rightarrow\left\{{}\begin{matrix}\left(x-2\right)^2=4\Rightarrow x-2=2\Rightarrow x=4\\y-3=-1\Rightarrow y=2\end{matrix}\right.\)