Áp dụng bđt |a|+|b| \(\ge\) |a+b| ta có:
|x-1|+|x-4| = |x-1|+|4-x| \(\ge\)|x-1+4-x| = 3
=> |x-1|+|x-2|+|y-3|+|x-4| \(\ge\) 3
Dấu "=" xảy ra khi \(\left\{\begin{matrix}x-1\ge0\\x-2=0\\y-3=0\\x-4\le0\end{matrix}\right.\)\(\Leftrightarrow\left\{\begin{matrix}x=2\\y=3\end{matrix}\right.\)
Vậy ...