\(2^{x+1}.7^{y-1}=98^{x+y}\)
\(\Leftrightarrow2.2^x.\frac{7y}{7}=98^x.98^y\)
\(\Leftrightarrow\frac{2}{7}=\left(\frac{98}{2}\right)^x.\left(\frac{98}{7}\right)^7\)
\(\Leftrightarrow\frac{2}{7}=49^x.14^y\)
\(\Leftrightarrow2.7^{-1}=7^{2x}.7^y.2^y\)
\(\Leftrightarrow2.7^{-1}=7^{2x+y}.2y\)
\(\Leftrightarrow2x+y=-1\Leftrightarrow\left\{{}\begin{matrix}y=1\\x=-1\end{matrix}\right.\)
Vậy...