Question

tìm x: x(x^2 +x +1) + x^2 + 2x + 1 - x^2(x+3) = 4

giúp mik với ạ 

mik cần gấp 

Answer 1

`x(x^2+x+1)+x^2+2x+1-x^2(x+3)=4`

`<=>x^3+x^2+x+x^2+2x+1-x^3-3x^2=4`

`<=>-x^2+3x-3=0`

`<=>x^2-3x+3=0`

`<=>x^2-2x . 3/2+9/4+3/4=0`

`<=>(x-3/2)^2=-3/4` (Vô lí)

Vậy ptr vô nghiệm

Answer 2

x =\(\dfrac{\sqrt{3i+}3}{2}\)

x = -\(\dfrac{\sqrt{3i-3}}{2}\)