a, \(x+\dfrac{2}{3}=0,2\)
\(\Rightarrow x+\dfrac{2}{3}=\dfrac{1}{5}\)
\(\Rightarrow x=\dfrac{1}{5}-\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{-7}{10}\)
b, \(\dfrac{17}{7}-\dfrac{6}{5}x=\dfrac{17}{4}\)
\(\Rightarrow\dfrac{6}{5}x=\dfrac{17}{7}-\dfrac{17}{4}\)
\(\Rightarrow\dfrac{6}{5}x=\dfrac{-51}{28}\)
\(\Rightarrow x=\dfrac{-51}{28}:\dfrac{6}{5}\)
\(\Rightarrow x=\dfrac{-85}{56}\)
\(a)\) \(x+\dfrac{2}{3}=0,2\)
\(\Rightarrow x+\dfrac{2}{3}=\dfrac{1}{5}\)
\(\Rightarrow x=-\dfrac{7}{15}\)
Vậy ...
\(b)\) \(\dfrac{17}{7}-\dfrac{6}{5}x=\dfrac{17}{4}\)
\(\Rightarrow\dfrac{6}{5}x=\dfrac{-51}{28}\)
\(\Rightarrow x=-\dfrac{85}{56}\)
Vậy ...
\(x=0,2-\dfrac{2}{3}\)
\(x=-\dfrac{7}{15}\)
\(-\dfrac{6}{5}x=\dfrac{17}{4}-\dfrac{17}{7}\)
\(-\dfrac{6}{5}x=\dfrac{51}{28}\)
\(x=\dfrac{51}{28}:\left(\dfrac{-6}{5}\right)\)
\(x=\dfrac{-85}{56}\)
\(x+\dfrac{2}{3}=0,2\left(a\right)\\ \Rightarrow x=0,2-\dfrac{2}{3}\\\Rightarrow x=\dfrac{1}{5}-\dfrac{2}{3}\\ \Rightarrow x=\dfrac{3}{15}-\dfrac{10}{15}\\ \Rightarrow x=-\dfrac{7}{15} \)
Vậy tập nghiệm phương trình (a) là \(\left\{-\dfrac{7}{15}\right\}\).
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\(\dfrac{17}{7}-\dfrac{6}{5}\cdot x=\dfrac{17}{4}\left(b\right)\\ \Leftrightarrow\dfrac{6}{5}x=\dfrac{17}{4}-\dfrac{17}{7}\\ \Leftrightarrow\dfrac{6}{5}x=\dfrac{119}{28}-\dfrac{68}{28}\\ \Leftrightarrow\dfrac{6}{5}x=\dfrac{51}{28}\\ \Rightarrow x=\dfrac{51}{28}:\dfrac{6}{5}\\ \Rightarrow x=\dfrac{51}{28}\cdot\dfrac{5}{6}\\ \Rightarrow x=\dfrac{255}{168}\\ \Rightarrow x=\dfrac{85}{56}\)
Vậy tập nghiệm phương trình (b) là \(\left\{\dfrac{85}{56}\right\}\).
\(x+\dfrac{2}{3}=0,2\)
x + \(\dfrac{2}{3}=\dfrac{1}{5}\)
x = \(\dfrac{1}{5}-\dfrac{2}{3}\)
x = \(\dfrac{3}{15}-\dfrac{10}{15}\)
\(x=\dfrac{3+\left(-10\right)}{15}\)
x = \(\dfrac{-7}{15}\)
Vậy x = \(\dfrac{-7}{15}\)
\(\dfrac{17}{7}-\dfrac{6}{5}.x=\dfrac{17}{4}\)
\(\dfrac{6}{5}.x=\dfrac{17}{7}-\dfrac{17}{4}\)
\(\dfrac{6}{5}.x=\dfrac{-51}{28}\)
\(x=\dfrac{-51}{28}:\dfrac{6}{5}\)
\(x=\dfrac{-51}{28}.\dfrac{5}{6}\)
\(x=\dfrac{-85}{56}\)
Vậy x = \(\dfrac{-85}{56}\)
