\(x\left(5-2x\right)+2x\left(x-1\right)=15\)
\(\Rightarrow5x-2x^2+2x^2-2x=15\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
Vậy x = 5.
\(x\left(5-2x\right)+2x\left(x-1\right)=15\)
\(\Leftrightarrow5x-2x^2+2x^2-2x=15\)
\(\Leftrightarrow3x=15\Leftrightarrow x=5\)
\(x.\left(5-2x\right)+2x.\left(x-1\right)=15\)
\(5x-2x^2+2x^2-2x=15\)
\(3x=15\)
\(x=5\)
\(x\left(5-2x\right)+2x\left(x-1\right)=15\)
\(\Rightarrow5x-2x^2+2x^2-2x=15\)
\(\Rightarrow\left(5x-2x\right)+\left(2x^2-2x^2\right)=15\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)