Question

Tìm x:  x^2(x+1)-x(x+1)+x(x-1)=0

MIK ĐANG CẦN GẤP

 

 

 

Answer 1

\(x^3+x^2-x^2-x+x^2-x=0\Leftrightarrow x^3+x^2=0\Leftrightarrow x^2\left(x+1\right)=0\Leftrightarrow x=0;x=-1\)

Answer 2

x²(x + 1) - x(x + 1) + x(x - 1) = 0

(x + 1)(x² - x) + x(x - 1) = 0

x(x + 1)(x - 1) + x(x - 1) = 0

x(x + 1)(x - 1 + 1) = 0

x(x + 1)x = 0

x²(x + 1) = 0

x² = 0 hoặc x + 1 = 0

*) x² = 0

x = 0

*) x + 1 = 0

x = 0 - 1

x = -1

Vậy x = -1; x = 0