\(x^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2=8^2\\x^2=\left(-8^2\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-8\end{matrix}\right.\)
Vậy ...
x2 = 16
=> x2 = ( \(\pm\)4 )2
=> x = 4 hoặc x = - 4
Tìm x:
\(x^2\)=16
\(x^2\)=\(4^2\)
\(\Rightarrow\)x=4