\(\left(x+1\right)^2-3\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x+1-3\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
Vậy phương trình có tập nghiệm \(S=\left\{-1;2\right\}.\)
Tìm x: a)(2x+1)(1-2x)+(1-2x)^2=18
b) 2(x+1)^2-(x-3)(x+3)-(x-4)^2=0
c) (x-5)^2-x(x-4)=9
d) (x-5)^2+(x-4)(1-x)=0
Tìm x biết
1.x(x+1)-x2+1=0
2.4x.(x-2)-6+3x=0
3.x(x+2)-3(x+2)=0
Tìm x biết
1.(x+3)2-(x+2).(x-2)=4x+17
2.(2x+1)2-(4x-1).(x-3)-15=0
3.(2x+3).(x-1)+(2x-3).(1-x)=0
4.2(5x-8)-3(4x-5)=4(3x-4)+11
5.(3x-1).(2x-7)-(1-3x).(6x-5)=0
tìm x
(2x-1)2+(x+3)2-5(x+7)(x-7) = 0
Bài 3: Tìm x biết:
1, \(4x^2-36=0\)
2, \(\left(x-1\right)^2+x\left(4-x\right)=11\)
3, \(\left(x-5\right)^2-x.\left(x+2\right)=5\)
4, \(x\left(x+4\right)-x^2-6x=10\)
Bài 1: Tìm GTNN
N= 2x^2+4y^2-2x-4y+15
Bài 2:Tìm X
a) (2x+3)^2-25(1-x)^2=0
(x-3)^3 +(x+3)^3=0
(x+1)^3-(x-1)^3=0
x^2-4x+3=0
4x^2 +4x +1=0
(x+2)^2-(x+3)^2=0
(x-3)^3 +(x+3)^3=0
(x+1)^3-(x-1)^3=0
x^2-4x+3=0
4x^2 +4x +1=0
(x+2)^2-(x+3)^2=0
a)(2x-1)^2+(x+3)^2-5(x+7)(x-7)=0
b)(x+2)(x^2-2x+4)-x(x^2+2)=15
c)(x+3)^3-x(3x+1)^2+(2x-1)(4x^2-2x+1)=28
d)(x^2-1)^3-(x^4+x^2+1)(x^2-1)=0
Tìm x biết
1. 2(5x-8)-3(4x-5)=4(3x-4)+11
2. (2x+1)2-(4x-1).(x-3)-15=0
3. (3x-1).(2x-7)-(1-3x).(6x-5)=0
