Question

Tìm x

x-\(\dfrac{1}{2}\) = -\(\dfrac{2}{3}\) \(\dfrac{2}{7}\)- x = -\(\dfrac{3}{4}\)

Answer 1

\(x-\dfrac{1}{2}=-\dfrac{2}{3}\\ x=-\dfrac{2}{3}+\dfrac{1}{2}\\ x=\dfrac{-1}{6}\) đây mà là toán lớp 7

\(\dfrac{2}{7}-x=-\dfrac{3}{4}\\ x=\dfrac{2}{7}+\dfrac{3}{4}\\ x=\dfrac{29}{28}\)

Answer 2

\(x-\dfrac{1}{2}=-\dfrac{2}{3}\)

\(x=-\dfrac{2}{3}+\dfrac{1}{2}\)

\(x=-\dfrac{1}{6}\)

Vậy ..................

\(\dfrac{2}{7}-x=-\dfrac{3}{4}\)

\(x=\dfrac{2}{7}+\dfrac{3}{4}\)

\(x=\dfrac{29}{28}\)

Vậy ..................