Ta có:x:8.32+x:3.18-x:5.10=120
=>x.4+x.6-x.2=120
=>x.(4+6-2)=120=>x.8=120
=>x=120:8=15
\(x:8.32+x:3.18-x:5.10=120\)
\(x.32:8+x.18:3-x.10:5=120\)
\(x.4+x.6-x.2=120\)
\(8x=120\)
\(x=120:8\)
\(x=15\)
Vậy \(x=15\) là giá trị cần tìm
\(x:8.32+x:3.18-x:5.10=120\)
\(x.(32:8)+x.(18:3)+x.(10:5)=120\)
\(4x+6x+2x=120\)
\(12x=120\)
\(x=120:12=10\)