\(\left(x-3\right)x\left(x-4\right)=0\)
+ \(x-3=0\) hoặc + \(x-4=0\)
+ \(x-3=0\)
\(x=0+3\)
\(x=3\)
+ \(x-4=0\)
\(x=0+4\)
\(x=4\)
Vậy \(x=3\) hoặc \(x=4\)
Giải:
\(\left(x-3\right)x\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x=0\\x-4=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\\x=4\end{matrix}\right.\)
Vậy ...