Question

Tìm x:

x+ \(3x^2\)=0

Answer 1

x+3x^2=0

x.(3x+1)=0

\(\Rightarrow\left[{}\begin{matrix}x=0\\3x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{-1}{3}\end{matrix}\right.\)

Vậy x=0 hoặc x=\(\dfrac{-1}{3}\)

Answer 2

x + 3x^2 = 0

<=> x ( 1+3x) = 0

<=> [ x = 0

1 + 3x = 0

<=> [ x= 0

x = -1/3