\(\left(x-3\right)^2-\left(x+3\right)=24\)
\(\Leftrightarrow x^2-6x+9-x-3-24=0\)
\(\Leftrightarrow x^2-7x-18=0\)
\(\Leftrightarrow x^2-9x+2x-18=0\)
\(\Leftrightarrow\left(x^2-9x\right)+\left(2x-18\right)=0\)
\(\Leftrightarrow x\left(x-9\right)+2\left(x-9\right)=0\)
\(\Leftrightarrow\left(x-9\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-9=0\\x+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=9\\x=-2\end{matrix}\right.\)
Vậy x=9 hoặc x=-2
(x-3)2-(x+3)=24
=>x2-6x+9-x-3-24=0
=>x2-7x-18=0
=>x2+2x-9x-18=0
=>(x2+2x)-(9x+18)=0
=>x(x+2)-9(x+2)=0
=>(x+2)(x-9)=0
=>\(\left[{}\begin{matrix}x+2=0\\x-9=0\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=-2\\x=9\end{matrix}\right.\)
vậy x=-2 hoặc x=9
