\(x-1+x-4=3x\)
\(\Leftrightarrow\left(x-x\right)+\left(-1-4\right)=3x\)
\(\Leftrightarrow0+\left(-5\right)=3x\)
\(\Leftrightarrow3x=-5\)
\(\Leftrightarrow x=-\frac{5}{3}\)
Vậy : \(x=-\frac{5}{3}\)
Mình sửa lại nhé, chưa đọc kĩ đề :
\(x-1+x-4=3x\)
\(\Leftrightarrow\left(x+x\right)+\left(-1-4\right)=3x\)
\(\Leftrightarrow2x-5=3x\)
\(\Leftrightarrow3x-2x=-5\)
\(\Leftrightarrow x=-5\)
Vậy \(x=-5\)
\(x-1+x-4=3x\\ \Leftrightarrow\left(x+x\right)+\left(-1-4\right)=3x\\ 2x-5=3x\\ -5=3x-2x\\ -5=x\\ \Rightarrow x\:=-5\)
